MCQs on Static Characteristics

1 - Question

What is the relative error percentage of an observation taken by an ultrasonic sensor which predicts the distance of an object to be 2.12cm but the actual value is 2cm?
a) 12%
b) 10%
c) 6%
d) 1%
View Answer Answer: c
Explanation: Given: Actual Value=2cm Measured Value=2.12cm Absolute error=Measured Value-Actual Value Absolute error=2.12cm-2cm=>0.12cm Relative error=(Absolute error/Actual Value)*100 Relative error=6%



2 - Question

What is the relative accuracy ratio of an observation taken by a distance measuring sensor which predicts the distance of an object to be 7.19cm but the actual distance is 7.02cm?
a) 13:719
b) 17:619
c) 17:702
d) 13:619
View Answer Answer: c
Explanation: Given: Actual Value=7.02cm Measured Value=7.19cm Absolute error=Measured Value-Actual Value Absolute error=7.19cm-7.02cm=0.17cm Relative accuracy=(Absolute error/Actual distance) Relative accuracy=(0.17/7.02)=>17:702



3 - Question

What is the mean value of a distance observation set taken by a distance measurement sensor? Observations={2,2.13,2.1,1.9}
a) 2.0325
b) 2.2
c) 2.125
d) 2
View Answer Answer: a
Explanation: Given: Observation set={2,2.13,2.1,1.9} Mean=Sum of observations/Total number of observations Mean=(2+2.13+2.1+1.9)/4 Mean=2.0325



4 - Question

Static characteristic of a sensor cannot be found using calibration.
a) True
b) False
View Answer Answer: b
Explanation: Static characteristic of a sensor can be found using calibration. Calibration refers to a comparison between a known or standard measurement to the unknown measurement taken by the tool which has to be calibrated.



5 - Question

What is the relative accuracy ratio of an observation taken by a IR(Infrared) sensor which predicts the distance of an object to be 1.26 cm but the actual distance is 1cm?
a) 13:409
b) 13:50
c) 17:719
d) 13:619
View Answer Answer: b
Explanation: Given: Actual Value=1cm Measured Value=1.26cm Absolute error=Measured Value-Actual Value Absolute error=1.26cm-1cm=>0.26cm Relative accuracy=(Absolute error/Actual distance) Relative accuracy=(0.26/1)=>13:50



6 - Question

Static characteristics of any sensor or transducer are determined by observing criteria’s that vary very slowly with time.
a) True
b) False
View Answer Answer: a
Explanation: Static characteristics of any sensor or transducer are determined by observing criteria’s that vary very slowly with time. Dynamic characteristics of any sensor or transducer are determined by observing criteria’s that vary rapidly with time.



7 - Question

Accuracy and precession are same for a sensor’s observation.
a) True
b) False
View Answer Answer: b
Explanation: Accuracy and precession are not same for a sensor’s observation. Accuracy is the observation closest to the true value whereas precession is the closeness of a observation among the predefined sets of observations.



8 - Question

Hysteresis error of any sensor has maximum difference between the observed value and actual value.
a) True
b) False
View Answer Answer: a
Explanation: Hysteresis error of any sensor has maximum difference between the observed value and actual value. Inside the specified range of the sensor, it is the maximum deviated observation from the actual observation.



9 - Question

What is the relative accuracy ratio of an observation taken by a IR(Infrared) sensor which predicts the distance of an object to be 4.16cm but the actual distance is 4.09cm?
a) 7:409
b) 13:603
c) 17:719
d) 13:619
View Answer Answer: a
Explanation: Given: Actual Value=4.09cm Measured Value=4.16cm Absolute error=Measured Value-Actual Value Absolute error=4.16cm-4.09cm=>0.07cm Relative accuracy=(Absolute error/Actual distance) Relative accuracy=(0.07/4.09)=>7:409



10 - Question

What is the relative error percentage of an observation taken by a distance measuring sensor which predicts the distance of an object to be 2.32cm but the actual value is 2cm?
a) 12%
b) 7.09%
c) 6%
d) 16%
View Answer Answer: d
Explanation: Given: Actual Value=2cm Measured Value=2.32cm Absolute error=Measured Value-Actual Value Absolute error=2.32cm-2cm=>0.32cm Relative error=(Absolute error/Actual Value)*100 Relative error=16%



11 - Question

What is the average value of a distance observation set taken by a ultrasonic sensor? Observations={5,5.413,5.41,4.97}
a) 5.0325
b) 5.198
c) 5.125
d) 5.07325
View Answer Answer: b
Explanation: Given: Observation set={5,5.413,5.41,4.97} Mean=Sum of observations/Total number of observations Mean=(5+5.413+5.41+4.97)/4 Mean=5.198



12 - Question

Static characteristics are related to the steady state response of an instrument.
a) True
b) False
View Answer Answer: a
Explanation: Static characteristics are related to the steady state response of an instrument. Steady state response of sensor is the relationship between input and output when the output changes very slowly or remains constant after a span of time. And static characteristics are the characteristics that changes very slowly or remains constant.



13 - Question

What is the mean value of a distance observation set taken by a distance measurement sensor? Observations={3,3.213,3.11,2.97}
a) 3.0325
b) 3.2
c) 3.125
d) 3.07325
View Answer Answer: d
Explanation: Given: Observation set={3,3.213,3.11,2.97} Mean=Sum of observations/Total number of observations Mean=(3+3.213+3.11+2.97)/4 Mean=3.07325



14 - Question

What is the relative accuracy ratio of an observation taken by a distance measuring sensor which predicts the distance of an object to be 6.16cm but the actual distance is 6.03cm?
a) 13:719
b) 13:603
c) 17:719
d) 13:619
View Answer Answer: b
Explanation: Given: Actual Value=6.03 cm Measured Value=6.16 cm Absolute error=Measured Value-Actual Value Absolute error=6.16cm-6.03cm=>0.13cm Relative accuracy=(Absolute error/Actual distance) Relative accuracy=(0.13/6.03)=>13:603



15 - Question

What is the relative error percentage of an observation taken by an infrared sensor which predicts the distance of an object to be 3.32cm but the actual value is 3.1cm?
a) 12%
b) 7.09%
c) 6%
d) 1%
View Answer Answer: b
Explanation: Given: Actual Value=3.1cm Measured Value=3.32cm Absolute error=Measured Value-Actual Value Absolute error=3.32cm-3.1cm=>0.22cm Relative error=(Absolute error/Actual Value)*100 Relative error=7.09%

Get weekly updates about new MCQs and other posts by joining 18000+ community of active learners