MCQs on Mechanics of Cutting-2
1 - Question
Chip flow velocity during machining process is 0.2m/s with chip thickness ratio of 0.6. What is the value of cutting velocity?
a) 0.33m/s
b) 0.43m/s
c) 0.23m/s
d) 0.13m/s
View Answer
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity. Hence cutting velocity = 0.33m/s.
2 - Question
Chip flow velocity during machining process is 1.2m/s with chip thickness ratio of 0.6. What is the value of cutting velocity?
a) 1.33m/s
b) 4m/s
c) 3m/s
d) 2m/s
View Answer
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity. Hence cutting velocity = 2m/s.
3 - Question
Shear velocity during machining process is 0.2m/s with chip thickness ratio of 0.6. Shear angle is 30 degree and rake angle is 15 degree. What is the value of cutting velocity?
a) 0.33m/s
b) 0.43m/s
c) 0.20m/s
d) 0.13m/s
View Answer
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity and chip flow velocity= shear velocity*sin (Shear angle)/(cos(rake angle)). advertisement
4 - Question
Shear velocity during the machining process is 1.2m/s with chip thickness ratio of 0.6. Shear angle is 30 degree and rake angle is 15 degree. What is the value of cutting velocity?
a) 0.33m/s
b) 0.43m/s
c) 1.20m/s
d) 0.13m/s
View Answer
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity and chip flow velocity= shear velocity*sin (Shear angle)/(cos(rake angle)).
5 - Question
Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of the shear angle in degrees?
a) 20.17
b) 44.13
c) 30.606
d) 21.571
View Answer
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Where r is the chip thickness ratio.
6 - Question
Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of shear force in Kg?
a) 20.17
b) 44.13
c) 30.606
d) 215.71
View Answer
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Shear force=Cutting force*cos(shear angle)-feed force*sin (shear angle).
7 - Question
Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of normal force in Kg?
a) 20.17
b) 44.13
c) 306.06
d) 215.71
View Answer
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Normal force=-Cutting force*sin (shear angle)+feed force*cos(shear angle).
8 - Question
Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of a coefficient of friction?
a) .20
b) .44
c) .97
d) .21
View Answer
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Use merchant circle diagram to find coefficient of friction.
9 - Question
Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of friction angle?
a) 20.17
b) 44.13
c) 30.606
d) 21.571
View Answer
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Use merchant circle diagram to find coefficient of friction and then use, Coefficient of friction= tan (friction angle).
10 - Question
Which of the following will have a maximum amount of chips during machining?
a) Ductile material
b) Brittle material
c) Cast iron
d) None of the mentioned
View Answer
Explanation: Ductile material produces more chip than brittle material.