# MCQs on Mechanics of Cutting-2

1 - Question

Chip flow velocity during machining process is 0.2m/s with chip thickness ratio of 0.6. What is the value of cutting velocity?
a) 0.33m/s
b) 0.43m/s
c) 0.23m/s
d) 0.13m/s
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity. Hence cutting velocity = 0.33m/s.

2 - Question

Chip flow velocity during machining process is 1.2m/s with chip thickness ratio of 0.6. What is the value of cutting velocity?
a) 1.33m/s
b) 4m/s
c) 3m/s
d) 2m/s
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity. Hence cutting velocity = 2m/s.

3 - Question

Shear velocity during machining process is 0.2m/s with chip thickness ratio of 0.6. Shear angle is 30 degree and rake angle is 15 degree. What is the value of cutting velocity?
a) 0.33m/s
b) 0.43m/s
c) 0.20m/s
d) 0.13m/s
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity and chip flow velocity= shear velocity*sin (Shear angle)/(cos(rake angle)). advertisement

4 - Question

Shear velocity during the machining process is 1.2m/s with chip thickness ratio of 0.6. Shear angle is 30 degree and rake angle is 15 degree. What is the value of cutting velocity?
a) 0.33m/s
b) 0.43m/s
c) 1.20m/s
d) 0.13m/s
Explanation: Chip flow velocity= chip thickness ratio * cutting velocity and chip flow velocity= shear velocity*sin (Shear angle)/(cos(rake angle)).

5 - Question

Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of the shear angle in degrees?
a) 20.17
b) 44.13
c) 30.606
d) 21.571
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Where r is the chip thickness ratio.

6 - Question

Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of shear force in Kg?
a) 20.17
b) 44.13
c) 30.606
d) 215.71
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Shear force=Cutting force*cos(shear angle)-feed force*sin (shear angle).

7 - Question

Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of normal force in Kg?
a) 20.17
b) 44.13
c) 306.06
d) 215.71
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Normal force=-Cutting force*sin (shear angle)+feed force*cos(shear angle).

8 - Question

Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of a coefficient of friction?
a) .20
b) .44
c) .97
d) .21
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Use merchant circle diagram to find coefficient of friction.

9 - Question

Feed force of 210Kg and cutting force of 310Kg are applied using a tool of rake angle 10 degrees. If chip thickness ratio is 0.36, what will be the value of friction angle?
a) 20.17
b) 44.13
c) 30.606
d) 21.571
Explanation: tan (shear angle)= (r*cos(rake angle))/ (1-r*sin(rake angle)). Use merchant circle diagram to find coefficient of friction and then use, Coefficient of friction= tan (friction angle).

10 - Question

Which of the following will have a maximum amount of chips during machining?
a) Ductile material
b) Brittle material
c) Cast iron
d) None of the mentioned