MCQs on Design of Helical Springs

1 - Question

If a spring has plain ends then number of inactive coils is?

a) 1
b) 2
c) 3
d) 0

View Answer

Answer: d
Explanation: There are no inactive coils in plain ends.




2 - Question

Spring having square ends has 1 inactive coil.

a) True
b) False

View Answer

Answer: b
Explanation: There are 2 inactive coils.




3 - Question

Martin’s factor compensates for curvature effect in springs.

a) True
b) False

View Answer

Answer: b
Explanation: Wahl’s factor accommodates curvature effect while designing spring.




4 - Question

The angle of twist for the equivalent bar to a spring is given by? (Symbols have their usual meaning)

a) 8PD²N/Gd⁴
b) 16PD²N/Gd⁴
c) 16PDN/Gdᵌ
d) 8PDN/Gdᵌ

View Answer

Answer: b
Explanation: θ=Ml/GJ where M=PD/2, l=πDN and J=πd⁴/32.




5 - Question

The axial deflection of spring for the small angle of θ is given by?

a) 328PDᵌN/Gd⁴
b) 8PDᵌN/Gd⁴
c) 16PDᵌN/Gd⁴
d) 8PD²N/Gdᵌ

View Answer

Answer: b
Explanation: Deflection=θxD/2.




6 - Question

A spring of stiffness constant k is cut in two equal parts. The stiffness constant of new spring will be k/2.

a) True
b) False

View Answer

Answer: b
Explanation: k=Gd⁴/8DᵌN, hence k is inversely proportional to number of coils. Thus result will be 2k.




7 - Question

For two spring connected in series, the force acting on each spring is same and equal to half of the external force.


a) True
b) False

View Answer

Answer: b
Explanation: Te force on each spring is equal to the external force.




8 - Question

For two springs connected in series, the net deflection is equal to the sum of deflection in two springs.


a) True
b) False

View Answer

Answer: a
Explanation: The net deflection is sum of the deflection of sprigs connected in series.




9 - Question

For two springs connected in parallel, net force is equal to the sum of force in each spring.

a) True
b) False

View Answer Answer: a Explanation: Net force applied is distributed in the two springs.



10 - Question

Patenting is defined as the cooling below the freezing point of water.

a) True
b) False

View Answer

Answer: b
Explanation: Patenting is heating steel above critical range followed by rapid cooling.




11 - Question

Find the Wahl’s factor if spring index is 6.

a) 1.2020
b) 1.2424
c) 1.2525
d) 1.5252

View Answer

Answer: c
Explanation: K=[4C-1/4C-4]+0.615/C.




12 - Question

Find the shear stress in the spring wire used to design a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm.

a) 452.2N/mm²
b) 468.6N/mm²
c) 512.2N/mm²
d) None of the listed

View Answer

Answer: b
Explanation: τ=K x 8PC/πd² where K=[4C-1/4C-4]+0.615/C.




13 - Question

Find the mean coil diameter of a helical compression sprig if a load of 1200N is applied on the spring. Spring index is 6, and wire diameter 7mm.

a) 7/6mm
b) 42mm
c) 1200×6/7 mm
d) None of the listed

View Answer

Answer: b
Explanation: D=Cd.




14 - Question

Find total number coils in a spring having square and ground ends. Deflection in the spring is 6mm when load of 1100N is applied. Modulus of rigidity is 81370N/mm². Wire diameter and pitch circle diameter are 10mm and 50mm respectively.
a) 7 b) 6 c) 5 d) 4
View Answer

Answer: a
Explanation: Deflection=8PDᵌN/Gd⁴ or N=4.4 or 5. Total coils=5+2(square grounded ends).




15 - Question

A railway wagon moving with a speed of 1.5m/s is brought to rest by bumper consisting of two springs. Mass of wagon is 100kg. The springs are compressed by 125mm. Calculate the maximum force acting on each spring.

a) 1200N
b) 1500N
c) 1800N
d) 2000N

View Answer

Answer: c
Explanation: mv²/2=Pxdeflection/2.

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