Avionics MCQs – Noise Suppression Effects of FM
1 - Question
Which of the following is not a source of noise in FM?
a) Weather
b) Electronic circuits
c) Lightning
d) Velocity of motion
View Answer
Explanation: Lightning strikes, ignition systems, motors, electronic circuits and weather create interference signals called noise. They are generally of high frequency and spikes of voltages.
2 - Question
Which circuit in FM receivers cancels or filters out noise?
a) Filter circuits
b) Anti-noise circuits
c) Limiter circuits
d) delimiter circuits
View Answer
Explanation: The receivers in FM contain limiter circuits which restrict the amplitude of the received signal. The noise which only affects the amplitude of the signal causes variations in amplitude of the signal. The limiter circuit clips off any variation in amplitude to filter out most of the noise.
3 - Question
Noise introduces a frequency variation into the signal.
a) True
b) False
View Answer
Explanation: The change in amplitude by the noise introduces a phase shift which is reflected as a small frequency variation in the signal. These frequency variations changes or distorts the signal.
4 - Question
What is the frequency deviation produced by noise if the signal to noise ratio is 3:1 and modulating frequency is 800Hz?
a) 152.32Hz
b) 482.5Hz
c) 132.8Hz
d) 271.Hz
View Answer
Explanation: ɸ=sin-1(N/S)=sin-1(1/3)=sin-1(0.3333)=19.47°=0.34rad δ=ɸ(fm)=0.34(800)=271.8Hz.
5 - Question
What is the noise to signal ratio if the phase shift introduced by noise is 0.75°?
a) 0.5
b) 0.966
c) 0.25
d) 1.75
View Answer
Explanation: ɸ=sin-1(N/S) (N/S)=sin(ɸ) =sin(75°)=0.966.
6 - Question
What is the frequency deviation produced by noise if the modulating frequency is 400Hz and the phase difference introduced by noise is 0.43rad?
a) 124Hz
b) 163Hz
c) 172Hz
d) 200Hz
View Answer
Explanation: δ=ɸ(fm)=0.43(400)=172Hz.
7 - Question
Calculate the phase difference by noise if the Signal to noise ratio is 7:2.
a) 15.366°
b) 17.5°
c) 13.65°
d) 8.21°
View Answer
Explanation: ɸ=sin-1(N/S)=sin-1(2/7)=sin-1(0.265)=15.366°.
8 - Question
What is the ratio of the shift produced by the noise to the maximum allowed deviation if the modulating frequency is 300Hz and the phase shift by noise is 25° and the maximum allowable deviation is 5kHz?
a) 1.3
b) 0.530
c) 0.153
d) 0.0261
View Answer
Explanation: δ=ɸ(fm)= 0.436(300)=130.89Hz Frequency deviation by noise / maximum deviation = 130.89/5000=0.0261.
9 - Question
What is the signal to noise ratio if the maximum allowable frequency deviation is 4kHz and the frequency deviation by noise is 156.42Hz?
a) 0.0364
b) 0.0391
c) 25.75
d) 20.45
View Answer
Explanation: N/S = Frequency deviation by noise / maximum deviation = 156.42/4000 =0.0391 S/N = (N/S)-1=25.57.
10 - Question
What is the technique in which the high frequency components are amplified more than the low frequency components in FM?
a) Garble
b) Preemphasis
c) Detoriation
d) Selective amplification
View Answer
Explanation: Preemphasis is a technique in which the high frequency signals are amplified more than the lower frequency signals to have better resistance to noise. It is usually used to transmit sounds from musical instruments which have high frequency harmonics.
11 - Question
Which of the following pairs of resistors and capacitors can be used in high pass filters for preemphasis circuits?
a) 100Ω and 0.075μF
b) 100Ω and 0.75μF
c) 150Ω and 0.75μF
d) 16Ω and 0.75μF
View Answer
Explanation: The time constant for a high pass filter to be used in the preemphasis circuit is 75μs. R x C = 75μs. Thus when R is 100Ω and C is 0.75μF, R x C = 75μs.
12 - Question
Find the frequency at which the signal enhancement flattens out in preemphasis circuit if R1=50Ω ,R2=70Ω and C=0.45μF.
a) 12126.09Hz b) 550Hz c) 10036..52Hz d) 9004.56Hz
View Answer
nswer: a
Explanation: 