Engineering Questions with Answers - Multiple Choice Questions

# Thermal Engineering MCQ’s – Draught – Definition and Classification

1 - Question

What is draught?
a) The condition of a dry boiler is called draught
b) It’s a small pressure difference which causes the flow of gases
c) It is a boiler mounting
d) It is a boiler accessory
Explanation: Draught is the small pressure difference which causes the flow of gas to take place. Draught helps to carry air to the fire-box and then take away the gaseous products of combustion out. Sufficient amount of air is necessary for proper combustion.

2 - Question

Draught is classified into _____
a) Artificial and natural draught
b) Induced and forced draught
c) Steam jet and mechanical draught
d) Chimney draught and boiler draught
Explanation: Draught is classified into artificial draught and natural draught. Natural draught is also known as chimney draught since it makes use of a chimney of sufficient height to create the required pressure difference.

3 - Question

Artificial draught is classified into steam jet and mechanical draught.
a) True
b) False
Explanation: Artificial draught is classified into steam jet and mechanical draught. Steam jet draught is further classified into induced and forced draught. Mechanical draught is classified into induced fan, balanced (induced and forced fan) and forced fan draught.

4 - Question

Natural draught is obtained using _____
a) Economizer
b) Induced fan
c) Chimney
d) Induced and forced fan
Explanation: Chimney is used to obtain natural draught. Chimney creates the necessary pressure difference for draught. Use of chimney also helps in discharging the products of combustion to a height where they won’t be affecting the surroundings.

5 - Question

Which of the following is the correct formula for calculating the pressure difference causing the gas flow through the combustion chamber?
a) (ρa – ρg)gH
b) (ρa + ρg)gH
c) (ρg – ρa)gH
d) (ρg + ρa)gH
Explanation: The correct formula for calculating the pressure difference causing the gas flow though the combustion chamber (or draught) is ‘(ρa – ρg)gH’.

6 - Question

Calculate the draught in mm of water if the chimney height is 30 m, the temperatures of hot gases inside chimney and outside air are 330°C and 30°C respectively. Also, the furnace is supplied with 15 kg of air per kg of coal burnt.
a) 14.67 mm of water
b) 17.64 mm of water
c) 16.22 mm of water
d) 16.19 mm of water
Explanation: H = 30 m, Tg = 330°C or 603 K, Ta = 30°C or 303 K, ma = 15 kg of air/kg of coal Draught in mm of water, hw = 353*H*{1Ta−1Tg(ma+1ma)} Substituting the respective values hw = 353*30*{1303−1603(1615)} hw = 16.22 mm of water

7 - Question

A chimney is 25 m high. The temperature of hot gases inside chimney is 300°C and temperature of air outside chimney is 30°C. If 20 kg of air is supplied to the furnace per kg of coal find the equivalent column of hot gases that would produce the same draught pressure.
a) 20.02 m
b) 22.40 m
c) 24.42 m
d) 22.60 m
Explanation: H = 25 m, Tg = 300°C or 573 K, Ta = 30°C or 303 K, ma = 20 kg of air/kg of coal Height of equivalent column of hot gases (burnt gases), H1 =H*{(mama+1)TgTa−1} Substituting the respective values H1 =25*{(2021)573303−1} H1 = 20.02 m

8 - Question

Calculate how much air is used per kg of coal burnt, if the chimney height is 35 m which creates a draught of 20 mm of water. The temperature of hot gases inside the chimney is 330°C and temperature of air outside is 27°C.
a) 29.52 kg of air per kg of coal
b) 21.34 kg of air per kg of coal
c) 22.45 kg of air per kg of coal
d) 19.54 kg of air per kg of coal
Explanation: H = 35 m, Tg = 330°C or 603 K, Ta = 27°C or 300 K, hw = 20 mm of water We know that, hw = 353*H*{1Ta−1Tg(ma+1ma)} After substituting the respective values 20 = 353*35*{1300−(ma+1ma)1603} Solving for ma we get ma = 29.52 kg of air per kg of coal

9 - Question

A 28 m chimney is full of hot gases at temperature 300°C. The air supplied for complete combustion of 1 kg of coal is 18 kg. calculate draught in N/m2 if the temperature of outside air is 25°C.
a) 140.32 N/m2
b) 187.54 N/m2
c) 150.32 N/m2
d) 146.76 N/m2
Explanation: H = 28 m, Tg = 300°C or 573 K, Ta = 25°C or 298 K, ma = 18 kg of air/kg of coal burnt draught (in N/m2) = 353*g*H*{1Ta−1Tg(ma+1ma)} substituting the respective values draught (in N/m2) = 353*9.81*28*{1298−1573(1918)} draught = 146.76 N/m2

10 - Question

A chimney 30 m high produces a draught of 16 mm of water. The temperature of hot gases inside the chimney is 300°C. Calculate the temperature of outside air if 20 kg of air is supplied for complete combustion of 1 kg of fuel.
a) 30°C
b) 27°C
c) 25°C
d) 20°C
Explanation: H = 30 m, hw = 16 mm of water, Tg = 300°C or 570 K, ma = 20 kg of air/kg of fuel we know that, hw = 353*H*{1Ta−1Tg(ma+1ma)} Substituting the respective values, we get, 16 = 353*30*{1Ta−1573(2120)} Solving for Ta we get, Ta = 299.1 ≈ 300 K or 27°C

11 - Question

Find the temperature of the hot gases inside the chimney if the draught produced by a 25 m high chimney is 15 mm of water. The temperature of the air outside is 25°C and 18 kg of air is supplied for complete combustion of 1 kg of fuel.
a) 298°C
b) 330°C
c) 456°C
d) 364°C
Explanation: H = 25, Ta = 25°C or 298 K, ma = 18 kg of air/kg of fuel, draught = 15 mm of water We know that, hw = 353*H*{1Ta−1Tg(ma+1ma)} Substituting the values 15 = 353*25*{1298−1Tg(1918)} Solving for Tg we get, Tg = 637.42 K ≈ 637 K or 364°C

12 - Question

Find draught in terms of column of hot gases, if the temperature of hot gases inside the chimney is 350°C. The height of the chimney is 30 m. The temperature of outside air is 25°C. The air supplied for complete combustion of 1 kg of fuel is 20 kg.
a) 29.73 m
b) 32.46 m
c) 45.32 m
d) 30.25 m
Explanation: H = 30 m, Tg = 350°C or 623 K, Ta = 25°C or 298 K, ma = 20 kg of air/kg of fuel We know that, draught in terms of column of hot gases is given by – H1 = H*{(mama+1)TgTa−1} Substituting the values H1 = 30*{(2021)623298−1} Therefore, H1 = 29.73 m

13 - Question

A 27 m high chimney produces a draught of 30 m in terms of Column of hot gases. The amount of air supplied for complete combustion of 1 kg of fuel is 20 kg. If the temperature of outside air is 27°C, determine the temperature of the hot gases inside the chimney.
a) 456°C
b) 392°C
c) 423°C
d) 398°C
Explanation: H = 27 m, H1 = 30 m (column of hot gases), ma = 20 kg of air/kg of fuel, Ta = 27°C or 300 K we know that, H1 =H*{(mama+1)TgTa−1} Substituting the values, we get 30 =27*{(2021Tg300−1} Solving for Tg, we get Tg = 665 K or 392°C

14 - Question

How much air is used per kg of coal burnt in a boiler having a chimney of height 32 m to create draught of 170 N/m2. The temperature of outside air is 25°C and hot gases inside chimney is 330°C.
a) 10.16 kg of air per kg of coal burnt
b) 12.00 kg of air per kg of coal burnt
c) 14.32 kg of air per kg of coal burnt
d) 19.25 kg of air per kg of coal burnt
Explanation: H = 32 m, draught = 170 N/m2, Ta = 25°C or 298 K, Tg = 330°C or 603 K The following formula is used to calculate draught in N/m2 – draught (in N/m2) = 353*g*H*{1Ta−1Tg(ma+1ma)} Substituting the respective values, we get 170 = 353*9.81*32*{1298−1603(ma+1ma)} Solving the above equation for ma, we get ma = 10.16 kg of air per kg of coal burnt

15 - Question

Find out the temperature of outside air if a chimney 30 m high creates a draught of 25 m in terms of column if hot gases. The temperature of hot gases is 330°C. 18 kg of air is to be supplied for complete combustion of 1 kg of fuel.
a) 38°C
b) 28°C
c) 25°C
d) 32°C

Explanation:
H = 30 m, H1 = 25 m of hot gases, Tg = 330°C or 603 K, ma = 18 kg of air/kg of fuel
we know that,
H1 =H*{mama+1TgTa−1}
Substituting the values, we get
25 =30*{1819603Ta−1}
Solving for Tg, we get
Tg = 311.6 K ≈ 311 K or 38°C
Symbols
ρa – mass density of air
ma – mass of air supplied per kg of fuel
ρg – mass density of hot gases
hw – draught in terms of column of water
H1 – draught in terms of column of hot gases
Ta – absolute temperature of atmosphere
Tg – average absolute temperature of chimney gases
g – gravitational acceleration
H – chimney height