Engineering Questions with Answers - Multiple Choice Questions

# The Dietert, Abbot Compaction Test and Jodhpur Mini Compactor Test

1 - Question

In Dietert test, the diameter of mould is _______ inches.
a) 2
b) 4
c) 6
d) 8

Explanation: The Dietert is a type of compaction test that is not mostly used. The apparatus for the test consists of a 2 inch diameter mould that is supported on a metal base by two pegs.

2 - Question

In Dietert test, the cylindrical weight falls through a height of ______ inches.
a) 2
b) 12
c) 18
d) 23

Explanation: In Dietert test, the cylindrical weight falls through a height of 2 inches. In Standard Proctor test, the height of free fall is 12 inches and for Modified Proctor test, the height of free fall is 18 inches.

3 - Question

In Abbot Compaction test, the internal diameter of the mould is ____________ cm.
a) 2
b) 3
c) 5.2
d) 10.15

Explanation: In Abbot Compaction test, the internal diameter of the mould is 5.2 cm. For the Standard Proctor test, the internal diameter of the mould is 10.15 cm.

4 - Question

In Abbot Compaction test, the effective height is ____________ cm.
a) 6
b) 11.7
c) 40
d) 50

Explanation: In Abbot Compaction test, the apparatus consists of a metal cylinder that has an effective height of 40 cm. For the Standard Proctor test, the height of the mould is 11.7 cm.

5 - Question

The height of free fall in Abbot compaction test is _______ cm.
a) 35
b) 31
c) 45.72
d) 43

Explanation: The height of free fall in Abbot compaction test is 35 cm above the base. For the Standard Proctor test, the height of free fall is 31 cm and for Modified Proctor test, the height of free fall is 45.72 cm.

6 - Question

In Jodhpur mini compaction test, the mould has internal diameter of ________ mm.
a) 79.8
b) 12.7
c) 45.72
d) 101.5

Explanation: In Jodhpur mini compaction test, the mould has internal diameter of 79.8 mm so that the cross-sectional area becomes 50 cm2. The Standard Proctor test mould has diameter of 101.5 mm.

7 - Question

In Jodhpur mini compaction test, the mould has effective height of ________ cm.
a) 6
b) 11.7
c) 40
d) 50

Explanation: In Jodhpur mini compaction test, the mould has effective height of 60 mm. In Abbot Compaction test, the apparatus consists of a metal cylinder that has an effective height of 40 cm. For the Standard Proctor test, the height of the mould is 11.7 cm.

8 - Question

In Jodhpur mini compaction test, the mould has capacity of ________ litre.
a) 0.3
b) 0.945
c) 0.5
d) 0.423

Explanation: In Jodhpur mini compaction test, the mould has effective height of 60 mm and internal diameter of 79.8 mm. Therefore the volume of the cylinder is,
πr2 h=π*79.82*60 mm3=0.3 litres.

9 - Question

In Jodhpur mini compaction test, the soil is compacted in ______ layers.
a) 1
b) 2
c) 5
d) 3

Explanation: In Jodhpur mini compaction test, the soil is compacted in 2 equal layers. In Modified Proctor test the number of layers of the soil is compacted is five. While in Standard Proctor test the number of layers of the soil is compacted is three.

10 - Question

In Jodhpur mini compaction test, a 2.5 kg DRT is used which falls freely from a height of ______ cm.
a) 35
b) 31
c) 45.72
d) 25

Explanation: In Jodhpur mini compaction test, a 2.5 kg DRT is used which falls freely from a height of 25 cm. The height of free fall in Abbot compaction test is 35 cm above the base. For the Standard Proctor test, the height of free fall is 31 cm and for Modified Proctor test, the height of free fall is 45.72 cm.

11 - Question

The water content used in field compaction is called _______
a) optimum water content
b) dry water content
c) placement water content
d) specific water content

Explanation: The water content used in field compaction is called as the placement water content. The optimum water content is the water content at which the soil attains its maximum density.

12 - Question

If weight of rammer is W, free fall height is h, number of layers is N, number of blows is n, acceleration due to gravity is g and volume as V, then the formula for energy per volume is ______
a) WhNngV
b) WVNngh
c) WhngN
d) WgNhnV

Explanation: The energy per volume formula is given by,
WhNngV,
where, W = weight of rammer
h = free fall height
N = number of layers
n = number of blows
g = acceleration due to gravity
V = volume.
The units of energy per volume is kJ/m3.

13 - Question

The energy per volume for Modified Proctor test is ______________
a) 593 kJ/m3
b) 2944 kJ/m3
c) 2674 kJ/m3
d) 4324 kJ/m3

Explanation: The energy per volume is,
WhNngV, and for Modified Proctor test,
W=4.54kg, h=457.2mm, N=5, n=25 and V=944 cc.
∴ EMPT=4.54*457.2*5*25/944
∴ EMPT=2674 kJ/m3.

14 - Question

The energy per volume for Light compaction test is ______________
a) 593 kJ/m3
b) 2944 kJ/m3
c) 2674 kJ/m3
d) kJ/m3

Explanation: The energy per volume is,
WhNngV, and for Light compaction test,
W=2.6kg, h=310mm, N=3, n=25 and V=1000 cc.
∴ ELCT=2.6*310*25*3/1000
∴ ELCT=593 kJ/m3

15 - Question

The energy per volume for Heavy compaction test is ______________
a) 593 kJ/m3
b) 2944 kJ/m3
c) 2674 kJ/m3
d) kJ/m3