Engineering Questions with Answers - Multiple Choice Questions
Stresses due to Self Weight
1 - Question
The stresses due to self weight of the soil are known as ______________
a) geostatic stresses
b) boundary stresses
c) external stresses
d) boundary strain
View Answer
Answer: a
Explanation: The stresses due to self weight of the soil are sometimes known as geostatic stresses. The self weight of the soil is found by the multiplication of unit weight of soil γ and the depth of the of the point in soil z.
σz=γz.
2 - Question
If XY pane is considered to be ground surface and the z-axis as depth, then this condition is known as _______
a) semi-infinite
b) infinite
c) finite
d) semi- finite
View Answer
Answer: a
Explanation: Semi-infinite condition is when one of the dimension extends to infinity. If XY pane is considered to be ground surface and the z-axis as depth, then this condition is known as semi-infinite.
3 - Question
When there is no eternal loading, the principal is _______
a) 5m below ground plane
b) ground plane
c) 10m below ground plane
d) at infinity
View Answer
Answer: b
Explanation: When there is no eternal loading, the ground plane becomes the principal plane. This is because the ground plane is devoid of any shear loading. The plane on which the shear stress is zero is called the principal plane and the normal stress on the principal plane is called the principal stress.
4 - Question
From the symmetry and orthogonality of principal planes ____________
a) both horizontal and vertical planes will be devoid of shear stress
b) both horizontal and vertical planes will have shear stress
c) only vertical plane has shear stress
d) only horizontal plane has shear stress
View Answer
Answer: a
Explanation: From the symmetry and orthogonality of principal planes, one can conclude that both horizontal and vertical planes will be devoid of shear stress.
∴ τYX= τYZ = τXZ=0.
5 - Question
The vertical stress at a point within soil mass at a depth z is ____________
a) σz=γ+z
b) σz=γ-z
c) σz=γ/z
d) σz=γz
View Answer
Answer: d
Explanation: From the symmetry and orthogonality of principal planes, one can conclude that both horizontal and vertical planes will be devoid of shear stress.
∴ τYX= τYZ = τXZ=0.
Substituting this in the equilibrium equation,
σz=γz.
6 - Question
On simplifying the compatibility equation in terms of stresses with respect to Poisson’s ratio is given by _________
a) σz=γz
b) σx=σy=μ1−μγz
c) σx=σy=1μγz
d) σx=σy=μγz
View Answer
Answer: b
Explanation: On simplifying the compatibility equation in terms of stresses with respect to Poisson’s ratio is given by
σx=σy=μ1−μγz
Where σx,σy are the normal stresses in x and y direction respectively
μ= Poisson’s ratio
Ko=μ1−μ is the coefficient of lateral pressure at rest.
7 - Question
f z-axis is considered to be directed downward from ground surface, then the stress component in y-axis at a point at a depth z due to self weight of soil above it is ___________
a) σy=11−μγz
b) σy=μγz
c) σy=μ1−μ
d) σy=μ1−μγz
View Answer
Answer: d
Explanation: On simplifying the compatibility equation in terms of stresses with respect to Poisson’s ratio is given by
\(σx=σy=\frac{μ}{1-μ}γz \)
Where σx,σy are the normal stresses in x and y direction respectively
μ= Poisson’s ratio
Ko=μ1−μ is the coefficient of lateral pressure at rest.
8 - Question
If z-axis is considered to be directed downward from ground surface, then the stress component in z-axis at a point at a depth z due to self weight of soil above it is ___________
a) σz=γz
b) σz=μγz
c) σz=μ1−μ
d) σz=μ1−μγz
View Answer
Answer: a
Explanation: When z-axis is considered to be directed downward from ground surface, then the stress component in z-axis at a point at a depth z due to self weight of soil above it is,
σz=γz, where σz is the normal the stress component in z-axis
γ=unit weight of soil
Z=depth at which the stress is calculated.
9 - Question
At a certain point within soil mass, the stresses are caused only because of surface loadings.
a) True
b) False
View Answer
Answer: b
Explanation: At a certain point within soil mass, the stresses are caused because of surface loadings as well as self-weight of the soil mass above that point. The surface loadings and the self-weight of the soil are calculated separately and then summed to get the total stress at a point.