Engineering Questions with Answers - Multiple Choice Questions

# Stresses due to Self Weight

1 - Question

The stresses due to self weight of the soil are known as ______________
a) geostatic stresses
b) boundary stresses
c) external stresses
d) boundary strain

Explanation: The stresses due to self weight of the soil are sometimes known as geostatic stresses. The self weight of the soil is found by the multiplication of unit weight of soil γ and the depth of the of the point in soil z.
σz=γz.

2 - Question

If XY pane is considered to be ground surface and the z-axis as depth, then this condition is known as _______
a) semi-infinite
b) infinite
c) finite
d) semi- finite

Explanation: Semi-infinite condition is when one of the dimension extends to infinity. If XY pane is considered to be ground surface and the z-axis as depth, then this condition is known as semi-infinite.

3 - Question

a) 5m below ground plane
b) ground plane
c) 10m below ground plane
d) at infinity

Explanation: When there is no eternal loading, the ground plane becomes the principal plane. This is because the ground plane is devoid of any shear loading. The plane on which the shear stress is zero is called the principal plane and the normal stress on the principal plane is called the principal stress.

4 - Question

From the symmetry and orthogonality of principal planes ____________
a) both horizontal and vertical planes will be devoid of shear stress
b) both horizontal and vertical planes will have shear stress
c) only vertical plane has shear stress
d) only horizontal plane has shear stress

Explanation: From the symmetry and orthogonality of principal planes, one can conclude that both horizontal and vertical planes will be devoid of shear stress.
∴ τYX= τYZ = τXZ=0.

5 - Question

The vertical stress at a point within soil mass at a depth z is ____________
a) σz=γ+z
b) σz=γ-z
c) σz=γ/z
d) σz=γz

Explanation: From the symmetry and orthogonality of principal planes, one can conclude that both horizontal and vertical planes will be devoid of shear stress.
∴ τYX= τYZ = τXZ=0.
Substituting this in the equilibrium equation,
σz=γz.

6 - Question

On simplifying the compatibility equation in terms of stresses with respect to Poisson’s ratio is given by _________
a) σz=γz
b) σxy=μ1μγz
c) σxy=1μγz
d) σxy=μγz

Explanation: On simplifying the compatibility equation in terms of stresses with respect to Poisson’s ratio is given by
σxy=μ1μγz
Where σxy are the normal stresses in x and y direction respectively
μ= Poisson’s ratio
Ko=μ1μ is the coefficient of lateral pressure at rest.

7 - Question

f z-axis is considered to be directed downward from ground surface, then the stress component in y-axis at a point at a depth z due to self weight of soil above it is ___________
a) σy=11μγz
b) σy=μγz
c) σy=μ1μ
d) σy=μ1μγz

Explanation: On simplifying the compatibility equation in terms of stresses with respect to Poisson’s ratio is given by
$$σxy=\frac{μ}{1-μ}γz$$
Where σxy are the normal stresses in x and y direction respectively
μ= Poisson’s ratio
Ko=μ1μ is the coefficient of lateral pressure at rest.

8 - Question

If z-axis is considered to be directed downward from ground surface, then the stress component in z-axis at a point at a depth z due to self weight of soil above it is ___________
a) σz=γz
b) σz=μγz
c) σz=μ1μ
d) σz=μ1μγz

Explanation: When z-axis is considered to be directed downward from ground surface, then the stress component in z-axis at a point at a depth z due to self weight of soil above it is,
σz=γz, where σz is the normal the stress component in z-axis
γ=unit weight of soil
Z=depth at which the stress is calculated.

9 - Question

At a certain point within soil mass, the stresses are caused only because of surface loadings.
a) True
b) False