Engineering Questions with Answers - Multiple Choice Questions
Separation Processes MCQ’s – The MSMPR Crystallization Model
1 - Question
In crystallization, solvent should dissolve large amount of solute at:
a) Room temperature
b) Boiling point
c) Freezing point
d) Slip melting point
View Answer
Answer: b
Explanation: Solvent should dissolve large amount of solute at boiling point of solvent.
2 - Question
Insoluble impurities during crystallization are removed by:
a) Decantation
b) Filtration
c) Distillation
d) Fractional crystallization
View Answer
Answer: b
Explanation: Since the impurities are insoluble they can be easily removed by filtration and no other methods are required
3 - Question
The crystals obtained in crystallization are dried by:
a) Dryer
b) Oven
c) Filter paper
d) Exposing to sun
View Answer
Answer: c
Explanation: The moisture is sucked with the help of a filter paper and the crystals are dried.
4 - Question
Which of the following is not an assumption of MSMPR model?
a) Perfect mixing of the magma
b) No crystal breakage
c) Continuous, steady-flow, steady-state operation
d) Crystals are of various sizes.
View Answer
Answer: d
Explanation: The crystals are assumed to be of same size in the MSMPR model.
5 - Question
What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 5
a) 0.01
b) 0.7
c) 0.6
d) 0.8
View Answer
Answer: a
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=0.01.
6 - Question
What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.05
a) 0.01
b) 0.7
c) 0.6
d) 100000
View Answer
Answer: d
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=1000000.
7 - Question
What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.78
a) 1.56
b) 2.34
c) 2.56
d) 0.8
View Answer
Answer: c
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=2.56.
8 - Question
What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.56
a) 5.67
b) 6.78
c) 7.11
d) 9.56
View Answer
Answer: c
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=7.11.
9 - Question
What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.67
a) 1.56
b) 7.89
c) 4.22
d) 4.15
View Answer
Answer: d
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=4.15.
10 - Question
What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 1m3
a) 0.5
b) 1.5
c) 1.8
d) 2.7
View Answer
Answer: c
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 1.8.
11 - Question
What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 0.5m3
a) 5.4
b) 3.6
c) 1.8
d) 2.7
View Answer
Answer: b
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 3.6.
12 - Question
What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.6
volume of mother liquor in magma V= 1m3
a) 1.45
b) 1.5
c) 1.07
d) 1.04
View Answer
Answer: d
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 1.04.
13 - Question
What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 0.5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 1m3
a) 0.5
b) 15
c) 1.8
d) 18
View Answer
Answer: d
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 18.
14 - Question
What is the nucleation rate if
Mass of production of crystals C=10kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 1m3
a) 9
b) 18
c) 180
d) 36
View Answer
Answer: c
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 180.