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Separation Processes MCQ’s – Slurry and Fixed Bed Adsorption Systems
What happens in a batch mode of contact filtration?
a) A batch of liquid is contacted with a batch of adsorbent for a period of time → followed by discharge of the slurry from the vessel, and filtration to separate solids from liquid
b) Liquid and adsorbent are continuously added to and removed from the agitated vessel
c) liquid is continuously fed, then removed from the vessel, where it is contacted with adsorbent, which is retained in a contacting zone of the vessel until it is nearly spent
d) Simultaneous continuous and batch mode operated
View Answer
Answer: a
Explanation: In the batch mode A batch of liquid is contacted with a batch of adsorbent for a period of time followed by discharge of the slurry from the vessel, and filtration to separate solids from liquid.
What happens in a batch mode of contact filtration?
a) A batch of liquid is contacted with a batch of adsorbent for a period of time followed by discharge of the slurry from the vessel, and filtration to separate solids from liquid
b) Liquid and adsorbent are continuously added to and removed from the agitated vessel
c) liquid is continuously fed, then removed from the vessel, where it is contacted with adsorbent, which is retained in a contacting zone of the vessel until it is nearly spent
d) Simultaneous continuous and batch mode operated
View Answer
Answer: b
Explanation: In the continuous mode Liquid and adsorbent are continuously added to and removed from the agitated vessel.
What happens in a batch mode of contact filtration?
a) A batch of liquid is contacted with a batch of adsorbent for a period of time followed by discharge of the slurry from the vessel, and filtration to separate solids from liquid
b) Liquid and adsorbent are continuously added to and removed from the agitated vessel
c) liquid is continuously fed, then removed from the vessel, where it is contacted with adsorbent, which is retained in a contacting zone of the vessel until it is nearly spent
d) Simultaneous continuous and batch mode operated
View Answer
Answer: c
Explanation: In the semi continuous mode liquid is continuously fed, then removed from the vessel, where it is contacted with adsorbent, which is retained in a contacting zone of the vessel until it is nearly spent.
Calculate the values of α is:
external liquid-phase mass-transfer coefficient k= 0.5
liquid volume Q= 100 litres
mass of adsorbentS = 5grams
a) 20
b) 40
c) 50
d) 60
View Answer
Answer: b
Explanation: Since α= Q/SK, α= 100/2.5=40.
Calculate the values of α is:
external liquid-phase mass-transfer coefficient k= 0.5
liquid volume Q= 100 litres
mass of adsorbentS = 10grams
a) 20
b) 40
c) 50
d) 60
View Answer
Answer: a
Explanation: Since α= Q/SK, α= 100/5=20.
a change in pressure has little or no effect on equilibrium loading for liquid adsorptionWhich of the following is untrue about pressure swing adsorption?
a) While one bed adsorbs, the other bed desorbs
b) Mechanical work is used to increase pressure
c) With valving, the cyclic sequence can be programmed to operate automatically
d) Applicable for only liquids
View Answer
Answer: d
Explanation: Applicable only for gases because a change in pressure has little or no effect on equilibrium loading for liquid adsorption.
Calculate the values of β is:
External liquid-phase mass-transfer coefficient k= 0.5
Liquid volume Q= 100 litres
Mass of adsorbent S = 8grams
a) 26
b) 48
c) 25
d) 60
View Answer
Answer: a
Explanation: Since β = 1+Q/SK, β =1+ 100/4=25.
Calculate the values of β is:
External liquid-phase mass-transfer coefficient k= 0.5
Liquid volume Q= 100 litres
Mass of adsorbent S = 10grams
a) 26
b) 48
c) 21
d) 60
View Answer
Answer: c
Explanation: Since β = 1+Q/SK, β =1+ 100/5=21.
Calculate the values of β is:
external liquid-phase mass-transfer coefficient k= 0.5
liquid volume Q= 100 litres
mass of adsorbentS = 16grams
a) 12.5
b) 13.5
c) 25
d) 27
View Answer
Answer: b
Explanation: Since β = 1+Q/SK, β =1+ 100/8=13.5.
Calculate the values of β is:
External liquid-phase mass-transfer coefficient k= 0.5
Liquid volume Q= 100 litres
Mass of adsorbent S = 6grams
a) 33.33
b) 35.33
c) 66.66
d) 34.33
View Answer
Answer: d
Explanation: Since β = 1+Q/SK, β =1+ 100/3=34.33.