Engineering Questions with Answers - Multiple Choice Questions
Separation Processes MCQ’s – Kremser Group Method
1 - Question
Many separators are cascades where two contacting phases flow __________
a) Co-currently
b) Counter-currently
c) Same direction
d) In any direction
View Answer
Explanation: Most of the cascades have contacting liquids flowing counter-currently.
2 - Question
Why the approximate calculations of composition of input and output field are called group methods?
a) Because they are found only in groups
b) Because only input-output group is there
c) Because they deal only with input-output calculation and don’t consider what exactly happens
d) It’s just a name
View Answer
Explanation: The approximate calculations of composition of input and output field are called group methods because they deal only with input-output calculation and don’t consider what exactly happens.
3 - Question
If KD = 2, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 2
d) 3
View Answer
Explanation: Since E= KDV/L, 2*100/300=0.67.
4 - Question
If KD = 2, amount of solvent (V)= 200kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1.3
c) 2.4
d) 3
View Answer
Explanation: Since E= KDV/L, 2*200/300=1.33.
5 - Question
If KD = 0.5, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 0.167
d) 3
View Answer
Explanation: Since E= KDV/L, 0.5*100/300=0.167.
6 - Question
If KD = 2, amount of solvent (V)= 100kg and amount of feed liquid is 100, what is the extraction factor?
a) 0.67
b) 1
c) 2
d) 3
View Answer
Explanation: Since E= KDV/L, 2*100/100=2.
7 - Question
If KD = 0.5, amount of solvent (V)= 500kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1.33
c) 2
d) 0.833
View Answer
Explanation: Since E= KDV/L, 0.5*500/300=0.833.
8 - Question
If KD = 3, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 2
d) 3
View Answer
Explanation: Since E= KDV/L, 3*100/300=1.
9 - Question
If KD = 2.5, amount of solvent (V)= 100kg and amount of feed liquid is 100, what is the extraction factor?
a) 0.67
b) 1
c) 2.5
d) 3
View Answer
Explanation: Since E= KDV/L, 2*100/300=0.67
10 - Question
If KD = 1, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 1.33
d) 0.33
View Answer
Explanation: Since E= KDV/L, 1*100/300=0.33.