Engineering Questions with Answers - Multiple Choice Questions

# Separation Processes MCQ’s – Hunter-Nash Graphical Equilibrium Stage Method

1 - Question

What is the type1 system for a solution?
a) The solute and solvent are immiscible in all proportions
b) The solute and solvent are miscible in all proportions
c) The concentration of solute is more than solvent
d) The concentration of solvent is more than solute
Explanation: For type1 system, the solute and solvent are miscible in all proportions.

2 - Question

What is the type2 system for a solution?
a) The solute and solvent are immiscible in all proportions
b) The solute and solvent are miscible in all proportions
c) The concentration of solute is more than solvent
d) The concentration of solvent is more than solute
Explanation: For type1 system, the solute and solvent are immiscible in all proportions.

3 - Question

How is phase equilibrium represented as told by hunter and nash?
a) Square
b) Oval
c) Equilateral triangle
d) Polygon
Explanation: According to hunter-nash method, an equilateral triangle is used to represent phase equilibrium.

4 - Question

What is the equilibrium curve in the liquid-liquid equilibrium data also called as?
a) Trinodal curve
b) Cynodal curve
c) Pinodal curve
d) Binodal curve
Explanation: It is called as bimodal curve since it has two nodes.

5 - Question

Solutropy is exhibited by which system?
a) Isopropanol-water-isopropyl alcohol
b) Water-benzene
c) Water-benzene-ethylalcohol
d) Isopropanol-water-benzene
Explanation: The phenomenon of solutropy is exhibited by the Isopropanol-water-benzene system.

6 - Question

What is the minimum solvent feed if feed is 200kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 200*(0.7-0.5/0.5-0.4)=400kg.

7 - Question

What is the minimum solvent feed if feed is 200kg and the mass fraction of component A at feed is 0.7, at mixing is 0.6, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 200*(0.6-0.5/0.5-0.4)=200kg.

8 - Question

What is the minimum solvent feed if feed is 250kg and the mass fraction of component A at feed is 0.8, at mixing is 0.5, and in the solvent is 0.4?
a) 3800kg
b) 650kg
c) 750kg
d) 500kg
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 250*(0.8-0.5/0.5-0.4)=750kg.

9 - Question

What is the minimum solvent feed if feed is 360kg and the mass fraction of component A at feed is 0.9, at mixing is 0.8, and in the solvent is 0.6?
a) 120kg
b) 720kg
c) 435kg
d) 180kg
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 360*(0.9-0.8/0.8-0.6)=180kg.

10 - Question

What is the minimum solvent feed if feed is 300kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 600kg
b) 100kg
c) 200kg
d) 500kg
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 300*(0.7-0.5/0.5-0.4)=600kg.

11 - Question

What is the minimum solvent feed if feed is 100kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 100*(0.7-0.5/0.5-0.4)=200kg.

12 - Question

What is the minimum solvent feed if feed is 320kg and the mass fraction of component A at feed is 0.6, at mixing is 0.5, and in the solvent is 0.3?
a) 430kg
b) 160kg
c) 540kg
d) 500kg
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 320*(0.6-0.5/0.5-0.3)=160kg.

13 - Question

What is the minimum solvent feed if feed is 50kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg