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Separation Processes MCQ’s – Hunter-Nash Graphical Equilibrium Stage Method
1 - Question
What is the type1 system for a solution?
a) The solute and solvent are immiscible in all proportions
b) The solute and solvent are miscible in all proportions
c) The concentration of solute is more than solvent
d) The concentration of solvent is more than solute
View Answer
Explanation: For type1 system, the solute and solvent are miscible in all proportions.
2 - Question
What is the type2 system for a solution?
a) The solute and solvent are immiscible in all proportions
b) The solute and solvent are miscible in all proportions
c) The concentration of solute is more than solvent
d) The concentration of solvent is more than solute
View Answer
Explanation: For type1 system, the solute and solvent are immiscible in all proportions.
3 - Question
How is phase equilibrium represented as told by hunter and nash?
a) Square
b) Oval
c) Equilateral triangle
d) Polygon
View Answer
Explanation: According to hunter-nash method, an equilateral triangle is used to represent phase equilibrium.
4 - Question
What is the equilibrium curve in the liquid-liquid equilibrium data also called as?
a) Trinodal curve
b) Cynodal curve
c) Pinodal curve
d) Binodal curve
View Answer
Explanation: It is called as bimodal curve since it has two nodes.
5 - Question
Solutropy is exhibited by which system?
a) Isopropanol-water-isopropyl alcohol
b) Water-benzene
c) Water-benzene-ethylalcohol
d) Isopropanol-water-benzene
View Answer
Explanation: The phenomenon of solutropy is exhibited by the Isopropanol-water-benzene system.
6 - Question
What is the minimum solvent feed if feed is 200kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 200*(0.7-0.5/0.5-0.4)=400kg.
7 - Question
What is the minimum solvent feed if feed is 200kg and the mass fraction of component A at feed is 0.7, at mixing is 0.6, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 200*(0.6-0.5/0.5-0.4)=200kg.
8 - Question
What is the minimum solvent feed if feed is 250kg and the mass fraction of component A at feed is 0.8, at mixing is 0.5, and in the solvent is 0.4?
a) 3800kg
b) 650kg
c) 750kg
d) 500kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 250*(0.8-0.5/0.5-0.4)=750kg.
9 - Question
What is the minimum solvent feed if feed is 360kg and the mass fraction of component A at feed is 0.9, at mixing is 0.8, and in the solvent is 0.6?
a) 120kg
b) 720kg
c) 435kg
d) 180kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 360*(0.9-0.8/0.8-0.6)=180kg.
10 - Question
What is the minimum solvent feed if feed is 300kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 600kg
b) 100kg
c) 200kg
d) 500kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 300*(0.7-0.5/0.5-0.4)=600kg.
11 - Question
What is the minimum solvent feed if feed is 100kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 100*(0.7-0.5/0.5-0.4)=200kg.
12 - Question
What is the minimum solvent feed if feed is 320kg and the mass fraction of component A at feed is 0.6, at mixing is 0.5, and in the solvent is 0.3?
a) 430kg
b) 160kg
c) 540kg
d) 500kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 320*(0.6-0.5/0.5-0.3)=160kg.
13 - Question
What is the minimum solvent feed if feed is 50kg and the mass fraction of component A at feed is 0.7, at mixing is 0.5, and in the solvent is 0.4?
a) 400kg
b) 100kg
c) 200kg
d) 500kg
View Answer
Explanation: Since, Smin/F= (xa)F-(xA)M/(xa)M-(xA)S , then, Smin= 50*(0.7-0.5/0.5-0.4)=100kg.