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# Mechanical Operations MCQ’s – Properties of Solid

Each dimensional formula is in which form?

a) [MLT]

b) [MDT]

c) [SDT]

d) [SVT]

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Answer: a

Explanation: Every dimensionless formula is represented as the function of the [MLT], where M is the mass, L is the length and T is the time.

The exponents of the formula can be _____

a) Only positive integers

b) Any Value

c) Only Fractions

d) Only Negative

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Answer: b

Explanation: All the exponents can be (α, β, ¥) integers either positive or negative and can also either be fractions or zero.

Flow rate can be expressed in dimensional formula as ____

a) MӨ^{-1}

b) MLT^{-1}

c) M^{-1}L

d) TL^{-2}

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Answer: a

Explanation: The flow rate can be expressed as Kg/s i.e. [Q] and hence [Q] = M/Ө = MӨ^{-1}.

On which of the listed, Reynold Number of flow depends upon?

a) Capacity, Mass and Diameter

b) Diameter, Length and Capacity

c) Diameter, Velocity and Viscosity

d) Velocity, Capacity and Pressure

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Answer: c

Explanation: The Reynolds number can be expressed as [DVP/U], where D is diameter, V is the velocity and P is taken as to be density and U is the viscosity.

Pressure drop can be dimensionally written as ____

a) [D/Ө^{-1}]

b) [F/L^{2}]

c) [MӨ^{-1}]

d) [MLӨ^{-1}]

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Answer: b

Explanation: The pressure drop can be written as kg/m^{2} as it is also same as force thus dimensionally [F/L^{2}], where F is the force and L is the length.

For Rayleigh’s Criteria, Minimum number of unrestricted components are ___

a) (n-r-3)

b) (n-r-2)

c) (n-r-1)

d) (n-r)

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Answer: b

Explanation: The number unrestricted components for Rayleigh’s Criteria is (n-r-2), where n = number of quantities and r is the primary dimensions.

The dimensions of density is?

a) [M/L]

b) [T/L^{2}]

c) [M/L^{3}]

d) [L/Ө]

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Answer: c

Explanation: The units of density is kg/m^{3}, hence the dimensions can written as M for mass and L raised to exponent (3), Thus [M/L^{3/sup>}

The working rule for the Buckingham π method is?

a) p=m-n

b) p=n-m

c) p=m-1

d) p=n-1

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Answer: b

Explanation: Langhoar has proved that for a number of dimensionless groups ‘P’ constituting a complete set for ‘n’ quantities is given by p=n-m.

The ‘P’ dimensionless groups are related as ____

a) Φ (π1, π2, π3, π4…) = 0

b) α (π1, π2, π3, π4…) = 0

c) β (π1, π2, π3, π4…) = 0

d) µ (π1, π2, π3, π4…) = 0

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Answer: a

Explanation: The ‘P’ dimensionless group are related to π1, π2, π3, π4… by the general formula as suggested by Buckingham.

What is the maximum value of m?

a) 4

b) 6

c) 7

d) 5

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Answer: d

Explanation: The maximum value of primary dimension that are (FMLӨT) is 5, these are fixed and hence cannot be changed.