Engineering Questions with Answers - Multiple Choice Questions

MCQs on Timings and Delays

1 - Question

If ‘n’ denotes the number of clock cycles and ‘T’ denotes period of the clock at which the microprocessor is running, then the duration of execution of loop once can be denoted by
a) n+T
b) n-T
c) n*T
d) n/T

View Answer

Answer: c
Explanation: The duration of execution of the loop is the product of number of clock cycles and the period of the clock cycle at which microprocessor is running.




2 - Question

The number of instructions actually executed by the microprocessor depends on the
a) stack
b) loop count
c) program counter
d) time duration

View Answer

Answer: b
Explanation: As the microprocessor executes each instruction corresponding loop counter value decreases and the microprocessor executes the instructions till the loop counter becomes zero.




3 - Question

In case of subroutines, the actual number of instructions executed by the processor depends on
a) loop count
b) length of interrupt service routine
c) length of procedure
d) none

View Answer

Answer: c
Explanation: In case of subroutines or interrupt service routines, the number of instructions executed by the processor depends on the length of procedure (or subroutine) or length of interrupt service routine along with the main calling program.




4 - Question

The step included in generating delays is
a) determining exact required delay
b) selecting instructions for delay loop
c) finding period of clock frequency
d) all of the mentioned

View Answer

Answer: d
Explanation: The delays can be generated step wise.




5 - Question

The Count, N can be defined as
a) required delay/duration for execution
b) duration of execution/required delay
c) required delay/number of clock cycles
d) required delay/period of clock frequency

View Answer

Answer: a
Explanation: The count N can be defined as the required time delay by the duration for execution of the loop once.
Count, N = required delay (Td)/duration for execution of the loop once (n*T).




6 - Question

In the instruction set,

      MOV CX, BA03H
WAIT: DEC CX
      NOP
      JNZ WAIT
      RET

if the zeroth condition is satisfied then, for execution, the JNZ instruction takes
a) 1 clock cycle
b) 2 clock cycles
c) 3 clock cycles
d) 4 clock cycles

View Answer

Answer: d
Explanation: The JNZ instruction takes only 4 clock cycles if the zeroth condition is satisfied.




7 - Question

In the instruction set,

      MOV CX, BA03H
WAIT: DEC CX
      NOP
      JNZ WAIT
      RET

if the zeroth condition is not satisfied, then the JNZ instruction takes
a) 2 clock cycles
b) 8 clock cycles
c) 16 clock cycles
d) 64 clock cycles

View Answer

Answer: c
Explanation: The JNZ instruction takes 16 clock cycles if the zeroth condition is not satisfied.




8 - Question

The maximum count value of 16-bit count register puts a limitation on
a) memory usage
b) storage of address of registers
c) to generate clock pulse
d) to generate maximum delay

View Answer

Answer: d
Explanation: The maximum count value of 16-bit count register is FFFFH. This may put the limitation on the maximum delay that can be generated using the instructions.




9 - Question

When large delays are required, then to serve the purpose
a) one or more count registers can be used
b) one or more shift registers can be used
c) one or more pointer registers can be used
d) one or more index registers can be used

View Answer

Answer: a
Explanation: One or more count registers can be used to serve large delays.

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