Engineering Questions with Answers - Multiple Choice Questions
MCQs on Newton- Rikhman Law
1 - Question
Newton-Rikhman law is given by
a) Q = h A (t s – t f)
b) Q = 2 h A (t s – t f)
c) Q = 3 h A (t s – t f)
d) Q = 4 h A (t s – t f)
View Answer
Answer: a
Explanation: Regardless of the particular nature, the appropriate rate equation for the convective heat transfer is prescribed by Newton’s law of cooling.
2 - Question
The value of film coefficient is dependent upon
(i) Boundary layer configuration
(ii) Geometry and orientation of the surface
(iii) Surface conditions
a) i and ii
b) ii and iii
c) i and ii
d) i, ii and iii
View Answer
Answer: d
Explanation: It depends upon surface conditions i.e. roughness and cleanliness, geometry and orientation of the surface i.e. plate, tube and cylinder placed vertically or horizontally.
3 - Question
The convection coefficients for boiling and condensation lie in the range
a) 5000-12500 W/m 2 K
b) 2500-100000 W/m 2 K
c) 2500-5000 W/m 2 K
d) 2500-12500 W/m 2 K
View Answer
Answer: b
Explanation: Convection mechanisms involving phase changes lead to important field of boiling and condensatio.
4 - Question
Forced air flows over a convection heat exchanger in a room heater, resulting in a convective heat transfer coefficient 1.136 k W/m2 K. The surface temperature of heat exchanger may be considered constant at 65 degree Celsius, and the air is at 20 degree Celsius. Determine the heat exchanger surface area required for 8.8 k W of heating
a) 0.272 m2
b) 0.472 m2
c) 0.172 m2
d) 0.672 m2
View Answer
Answer: c
Explanation: Q = h A (t s – t f). So. A = 0.172 m2.
5 - Question
A region of fluid motion near a plate in which temperature gradient exist is
a) Thermal boundary layer
b) Diathermia boundary layer
c) Turbulent flow
d) Laminar flow
View Answer
Answer: a
Explanation: The fluid velocity decreases as it approaches the solid surface reaching to zero in the fluid layer immediately next to the surface. The thin layer of stagnated fluid is called thermal boundary layer.
Explanation: The fluid velocity decreases as it approaches the solid surface reaching to zero in the fluid layer immediately next to the surface. The thin layer of stagnated fluid is called thermal boundary layer.
6 - Question
Thermo-physical properties of the fluid are represented by
(i) Density
(ii) Viscosity
(iii) Specific heat
(iv) Thermal conductivity
Identify the correct option
a) i and ii
b) i, ii, iii and iv
c) ii, iii and iv
d) i, ii and iii
View Answer
Answer: b
Explanation: The value of film coefficient is dependent upon thermos-physical properties of he fluid i.e. density, viscosity, specific heat, coefficient of expansion and thermal conductivity.
7 - Question
A motor cycle cylinder consists of ten fins, each 150 mm outside diameter and 75 mm inside diameter. The average fin temperature is 500 degree Celsius and the surrounding air is at 20 degree Celsius temperature. Make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is stationary and convective coefficient is 6 W/m2 K
a) 432.2 W
b) 532.2 W
c) 632.2 W
d) 763.2 W
View Answer
Answer: d
Explanation: A = 0.265 m2 and Q = (6) (0.265) (500 – 20) = 763.2 W.
8 - Question
Consider the above problem, make calculations for the rate of heat dissipation from the cylinder fins by convection when motor cycle is moving at 60 km/hr and convective coefficient is 75 W/m2 K
a) 9640 W
b) 9540 W
c) 9440 W
d) 9340 W
View Answer
Answer: b
Explanation: A = 0.265 m2 and Q = (75) (0.265) (500 – 20) = 9540 W.
9 - Question
The temperature profile at a particular location on a surface is prescribed by the identity
(t s – t) / (t s – t infinity) = (1/2) (y/0.0075) 3 + (3/2) (y/0.0075)
If thermal conductivity of air is stated to be 0.03 W/m K, determine the value of convective heat transfer coefficient
a) 4 W/m2 K
b) 5 W/m2 K
c) 6 W/m2 K
d) 7 W/m2 K
View Answer
Answer: c
Explanation: h = – k/ (t s – t infinity) [d t/d y] y = 0.
10 - Question
Air at 20 degree Celsius flows over a flat surface maintained at 80 degree Celsius. The local heat flow at a point was measured as 1250 W/m2 .Take thermal conductivity of air as 0.028 W/m K, calculate the temperature at a distance 0.5 mm from the surface
a) 57.682 degree celsius
b) 67.682 degree celsius
c) 77.682 degree celsius
d) 87.682 degree celsius
View Answer
Answer: a
Explanation: Temperature at 0.5 mm from the surface is 80 + (d t/d y) y = 0 (0.0005) = 57.682 degree celsius.