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MCQs on Conductivity of a Semiconductor
What is the SI unit of conductivity?
a) Ωm
b) (Ωm)-1
c) Ω
d) m
View Answer
Answer: b
Explanation: The formula of the conductivity is the σ=1/ρ.
So, the unit of resistivity is Ωm.
Now, the unit of conductivity becomes the inverse of resistivity.
Which of the following expressions doesn’t represent the correct formula for Drift current density?
a) J=σE
b) J=qnµE
c) J=µE
d) None
View Answer
Answer : c
Explanation: The following formulae represent the correct expression for drift current density,
J=σE
And J=qnµE.
Does a semiconductor satisfy the ohm’s law?
a) True
b) False
View Answer
Answer: a
Explanation: V=IR
J=σE
I/A=σ(V/L)
V=(L/ σA)*I=(ρL)*I/A=IR
Thus, above equation satisfies Ohm’s law.
In which range of temperature, freeze out point begins to occur?
a) Higher range
b) Lower range
c) Middle range
d) None
View Answer
Answer: b
Explanation: At lower range of temperature, the concentration and conductivity decreases with lowering of the temperature.
Which of the following expression represents the correct formula for the conductivity in an intrinsic material?
a) ρ=e(μn+μp )ni
b) σ=e(μn+μp )ni
c) σ=1/(e(μn+μp )ni)
d) ρ=1/(e(μn+μp )ni)
View Answer
Answer: b
Explanation: Option b is the correct formula.
What is the voltage difference if the current is 1mA and length and area is 2cm and 4cm2 respectively?(ρ=2Ωm)
a) 0.025V
b) 25V
c) 0.25V
d) None
View Answer
Answer: d
Explanation: V=IR
R=ρl/(A)=2*2/4=100Ω
V=1mA*100
=0.1V.
Is resistivity is a function of temperature?
a)True
b)False
View Answer
Answer: a
Explanation: Resistance depends on the temperature and the resistivity depends on the resistance, so now the resistivity depends on the temperature.
What is the electric field when the voltage applied is 5V and the length is 100cm?
a) 0.5V/m
b) 5V/m
c) 50V/m
d) None
View Answer
Answer: c
Explanation: E=V/L=5/100cm=5V/m.
Calculate the average random thermal energy at T=300K?
a) 0.038eV
b) 3.8eV
c) 38eV
d) 0.38eV
View Answer
Answer: a
Explanation: Average random thermal energy=3/2*k*T=0.038eV.
In the above figure, a semiconductor having an area ‘A’ and length ‘L’ and carrying current ‘I’ applied a voltage of ‘V’ volts across it. Calculate the relation between V and A?
a) V= ((ρ*L)/A)*I
b) V= ((ρ*A)/L)*I
c) V= ((ρ*I)/(A*L))
d) V=((ρ*I*A*L)
View Answer
Answer: a
Explanation: Option A, satisfies the Ohm’s law which is V=IR where R=(ρl)/A.