Engineering Questions with Answers - Multiple Choice Questions

Machine Dynamics MCQ – Isochronous Governor

1 - Question

When equilibrium speed is constant, then the governor is called ______
a) Pickering
b) Hartung
c) Porter
d) Isochronous

Explanation: Pickering, Porter and Hartung are different categories of governor whereas Isochronous describes the property of the governor by the virtue of which the range in equilibrium speed is zero.

2 - Question

For isochronism, range of speed should be equal to mean speed.
a) True
b) False

Explanation: Isochronism describes the property of the governor by the virtue of which the range in equilibrium speed is zero.

3 - Question

The sensitiveness of an isochronous governor is ______
a) 0
b) 2
c) 1/2
d) 1

Explanation: For isochronisms N1 – N2 = 0, since this range is 0, the sensitiveness will also be equal to as
sensitiveness = (N1 – N2)÷N.

4 - Question

Which of the following type of governor cannot be isochronous?
a) Pickering
b) Porter
c) Hartung
d) Hartnell

Explanation: For a porter governor it is impossible to have the two balls moving at the same speed, thus the range cannot be 0 which makes it impossible to be an isochronous governor.

5 - Question

An isochronous governor is not practical because of the following reason.
a) Friction at the sleeve
b) Weight of the spring
c) Impossible to achieve 0 range
d) High use of porter governors

Explanation: The isochronous governor is not of practical use because the sleeve will move to one of its extreme positions immediately the speed deviates from the isochronous speed.

6 - Question

The sensitivity of a governor is 0, and the mean speed is 25 rpm, then it is not possible that the governor will be ________
a) Pickering
b) Porter
c) Hartung
d) Hartnell

Explanation: For a porter governor it is impossible to have the two balls moving at the same speed, thus the range cannot be 0 which makes it impossible to be an isochronous governor. Since sensitiveness is 0, therefore range is 0 hence the governor cannot be porter.

7 - Question

For a Hartnell governor which of the following relation regarding r₁/r₂ is true for isochronisms?
a) (M.g + S1) ÷ (M.g + S2)
b) (M.g + S2) ÷ (M.g + S1)
c) S2/ S1
d) S1/ S2

Explanation: For isochronisms the equilibrium speed should remain constant throughout, i.e Range should be 0.
Applying that condition we have r1/r2 = (M.g + S1) ÷ (M.g + S2)

8 - Question

Pendulum type governor cannot be isochronous
a) True
b) False