Engineering Questions with Answers - Multiple Choice Questions
Machine Dynamics MCQ – Coefficient of Fluctuation of Energy
1 - Question
In the figure given below, the areas BbC, CcD represent _______
a) Power generated
b) Power lost
c) Fluctuation of energy
d) Change in momentum
View Answer
Answer: c
Explanation: The variations of energy above and below the mean resisting torque line are called fluctuations of energy. The areas under the following curves: BbC, CcD, DdE and so on represent fluctuations of energy.
2 - Question
The fluctuation of energy is the variation of energy above the line of minimum torque.
a) True
b) False
View Answer
Answer: b
Explanation: The given statement is false because the variations of energy above and below the mean resisting torque line are called fluctuations of energy. It is represented by the enclosing curves above and below the mean line.
3 - Question
From the turning moment diagram shown below, the maximum speed will occur at point
a) p
b) b
c) q
d) c
View Answer
Answer: c
Explanation: The maximum engine speed occurs at point q because the flywheel absorbs energy when the crank moves from point p to q. This results in a gain of speed.
4 - Question
From the turning moment diagram shown below, the minimum speed will occur at point
a) p
b) b
c) q
d) c
View Answer
Answer: a
Explanation: The minimum engine speed occurs at point p because the flywheel gives out some of its energy when the crank moves from point a to p. This results in loss of speed
5 - Question
Coefficient of fluctuation of energy is ratio of _______
a) Mean fluctuation energy to work done per cycle
b) Maximum fluctuation energy to work done per cycle
c) Minimum fluctuation energy to work done per cycle
d) Mean fluctuation energy to power generated per cycle
View Answer
Answer: b
Explanation: The ratio of the maximum fluctuation of energy to the work done per cycle is known as the coefficient of fluctuation of energy. Mathematically, coefficient of fluctuation of energy (CE) = Maximum fluctuation of energy/Work done per cycle.
6 - Question
Work done per cycle is calculated as _______
a) Tmean × θ
b) Tmin × θ
c) Tmax × θ
d) Tmax × θ/2
View Answer
Answer: a
Explanation: The work done per cycle (in N-m or joules) may be obtained by using the following relations: Work done per cycle = Tmean × θ, where Tmean = Mean torque, Mean torque is same as the mean resisting torque.
7 - Question
For a 4 stroke IC engine, the angle θ assumes a value equal to _______
a) π
b) 2π
c) 4π
d) π/2
View Answer
Answer: c
Explanation: For a 4 stroke internal combustion engine, a power stroke takes place every 2 revolution therefore the total angle turned is equal to 4π.
8 - Question
To calculate power generated, product of maximum torque and angular speed is taken.
a) True
b) False
View Answer
Answer: b
Explanation: To calculate power generated, product of mean effective torque and angular speed is taken.
P = Tmean × ω
9 - Question
For a 4 stroke IC engine, Tmean = 1875 N-m, then find the work done per cycle.
a) 23.56 kJ
b) 11.78 kJ
c) 5.89 kJ
d) 2.94 kJ
View Answer
Answer: a
Explanation: For a 4 stroke internal combustion engine, a power stroke takes place every 2 revolution therefore the total angle turned is equal to 4π. Hence θ=4π
therefore work done per cycle = 23.56 kJ.
10 - Question
A shaft fitted with a flywheel rotates at 250 r.p.m. and drives a machine, the torque fluctuated about 18750 N-m, find the power required to drive the machine.
a) 49.125 kW
b) 24.56 kW
c) 12.28 kW
d) 6.14 kW
View Answer
Answer: a
Explanation: ω = 2π × 250/60 = 26.2 rad/s,
P = Tmean ×ω
= 1875 x 26.2
= 49.125 kW.