Engineering Questions with Answers - Multiple Choice Questions

Determination of Coefficient of Consolidation – 2

1 - Question

The graph is plotted with the procedure of square root of time fitting method. The line B is drawn that its abscissa at every point is ______ times that of line A.

a) 1.40
b) 1.30
c) 1.15
d) 0

View Answer

Answer: c
Explanation: When the graph is plotted with the procedure of square root of time fitting method. The line B is drawn that its abscissa at every point is 1.15 times that of line A. The line B is drawn from Rc, instead of the initial reading R0.




2 - Question

 The average drainage path for the pressure increment is calculated from the formula of ______
a) d=12[HHf2]
b) d=12[H2]
c) d=12[HHf4]
d) d=12[HfH2]

View Answer

Answer: a
Explanation: The average drainage path for the pressure increment is calculated from the formula of,
d=12[HHf2]
where, H1=initial height of the specimen under initial load
and Hf=final height of the specimen under final load.




3 - Question

The logarithm of time fitting method was suggested by ______
a) Terzaghi
b) Taylor
c) Darcy
d) A.Casagrande

View Answer

Answer: d
Explanation: The logarithm of time fitting method was suggested by A.Casagrande in 1930. The use of square root of fitting method was suggested by Taylor in 1948. Darcy did his research in the permeability of soils.




4 - Question

 In logarithm of time fitting method, the graph is drawn on a ____________
a) radial graph
b) linear graph
c) semi-log plot
d) log-log plot

View Answer

Answer: c
Explanation: In logarithm of time fitting method, the graph is drawn on a in which the degree of consolidation (U) or the dial readings (R) are plotted in the linear scale and the logarithm of time (log t) in the log scale.




5 - Question

 The logarithm of time fitting method is based on the characteristic of ______________
a) U and Tv
b) U and log10⁡Tv
c) Tv
d) log10Tv

View Answer

Answer: b
Explanation: The logarithm of time fitting method is based on the characteristic of U and log10Tv in the intersection of the tangent at the point of inflection and the asymptote of the lower portion is at the ordinate of 100% U.




6 - Question

 The primary consolidation is from _____________

a) R100 to Rf
b) R10 to Rc
c) R1 to Rc
d) Rc to R100

View Answer

Answer: d
Explanation: The consolidation from Rc to R100 is the primary consolidation. The dial reading R100 is given by extending the straight portion of curve to meet the point of 100% consolidation.




7 - Question

 The secondary consolidation is from __________

a) R10 to Rf
b) R100 to Rf
c) Rc to R100
d) Rf to R100

View Answer

Answer: b
Explanation: The consolidation from R100 to Rf is the secondary consolidation. Usually the secondary consolidation in most of the problems is neglected because of the time it takes to consolidate.




8 - Question

 For logarithm of time fitting method, the coefficient of consolidation is detained from ________
a) cv=(Tv)70d3t70
b) cv=(Tv)80d2t80
c) cv=(Tv)90d4t90
d) cv=(Tv)50d2t50

View Answer

Answer: d
Explanation: For logarithm of time fitting method, the coefficient of consolidation is detained from,
cv=(Tv)50d2t50
where, cv=coefficient of consolidation
(Tv)50=time factor corresponding to 50% consolidation
t50=elapsed time for 50% consolidation
d=average drainage path for pressure increment.




9 - Question

 From the coefficient of consolidation and coefficient of volume change, the coefficient of permeability is found by equation ____________
a) k=mv γv
b) k=Cv γv
c) k=Cv mv γv
d) k=Cv mv

View Answer

Answer: c
Explanation: The coefficient of consolidation is given by the formula,
Cv=kmvγv. Therefore, on rearranging the equation,
∴ k=Cv mv γv.




10 - Question

 From the coefficient of consolidation and coefficient of compressibility, the coefficient of permeability is found by equation __________
a) k=γw1+eo
b) k=CvavAγw1+eo
c) k=avγw1+eo
d) k=Cvavγw1+eo

View Answer

Answer: d
Explanation: Since the coefficient of permeability is given by the equation,
k=Cv mv γw —————–(1)
The coefficient of volume change is given by,
mv=av1+e0, therefore substituting in (1),
k=Cvavγw1+eo.

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